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--- Thread: [Plugin] Sscanf problem (/showthread.php?tid=1168)
Sscanf problem - Pinch - 2020-08-27
Code:
if(sscanf(inputtext, "{s[32]'@'s[32]'.'s[16]}"))Always positive, even if I enter something like [email protected]
I'm using sscanf 2.10.2
RE: Sscanf problem - Tama - 2020-08-27
I think it's nearly impossible using only sscanf, you should replace '@' and '.' to space and check it like this:
PHP Code:
if (sscanf(inputtext, "{sss}"))
Or you can just see my code below:
https://gist.github.com/se8870/ca137f685298c06fea7d7abb861f2202
RE: Sscanf problem - Pinch - 2020-08-27
(2020-08-27, 09:10 PM)Tama Wrote: I think it's nearly impossible using only sscanf, you should replace '@' and '.' to space and check it like this:
PHP Code:if (sscanf(inputtext, "{sss}"))
Or you can just see my code below:
https://gist.github.com/se8870/ca137f685298c06fea7d7abb861f2202
Nope, you cannot use s without length.
I already fixed this but this is an sscanf bug I think
idk why is search ' ' broken smh
RE: Sscanf problem - Tama - 2020-08-28
(2020-08-27, 09:41 PM)Pinch Wrote: Nope, you cannot use s without length.
Still work but you're get an error.
That code it's just example for older version.
RE: Sscanf problem - Pinch - 2020-08-28
I'm using sscanf 2.10.2 which turns warnings into errors...
RE: Sscanf problem - Y_Less - 2020-09-23
Search works fine, but you don't want search. `s` can contain `@`, so if you type `[email protected]` sscanf will do the following:
`s[32]` - Gathers everything until the first separator (whitespace by default), so `[email protected]`.
`'@'` - Looks for another `@`, but there isn't one, so the check fails.
You are missing up searches and delimiters. sscanf doesn't have look-ahead/look-behind, so while it is reading a string it doesn't know that the NEXT instruction is to look for an `@`. You've not told sscanf to stop reading strings at `@`, so it doesn't. You want:
"p<@>s[32]s[32] "
(you also don't want to check for a `.`, as valid e-mail addresses don't have to have one. Really all you want is `strfind(input, "@") != -1` - that's the simplest way to look for a valid e-mail address. Of course the only truly correct way is to send an e-mail it it.