2023-12-11, 07:55 PM
(This post was last modified: 2023-12-12, 09:02 PM by BotLevel.Bobu.)
How to stop a timer. The " stop x " doesn't work. It is a BUG or I don't use it right ?
https://tinypic.host/image/LqSj4
And now I'm using qanwo with the latest release from YSI and still exact the same problem.
https://tinypic.host/image/LzMcb
Now I really think that I'm using it wrong because not even the normal way doesn't work.
I found the right way.
Like I thought... I wasn't use it right ! Everything work just perfect !
This is how it works:
Code:
#include <a_samp>
#include <YSI_Coding\y_timers>
main()
{
print("Start Timer Test2");
defer Test2();
}
timer Test1[10000]()
{
print(" Why still working ? Why calling this timer 2x ?");
return 1;
}
timer Test2[5000]()
{
print(" Timer Test2 5 sec ");
defer Test3();
defer Test1();
return 1;
}
timer Test3[2000]()
{
print(" Timer Test3 6 sec ");
stop Test1(); // It seems that simply calls the function instantly and not stoping anything ... That's why calling the timer 2x
return 1;
}
https://tinypic.host/image/LqSj4
And now I'm using qanwo with the latest release from YSI and still exact the same problem.
Code:
#include <open.mp>
#define YSI_NO_HEAP_MALLOC
#include <YSI_Coding\y_timers>
timer Test1[10000]()
{
print(" Why still working ? Why calling this timer 2x ?");
return 1;
}
timer Test3[2000]()
{
print(" Timer Test3 6 sec ");
stop Timer:Test1(); // It seems that simply calls the function instantly and not stoping anything ... That's why calling the timer 2x
return 1;
}
timer Test2[5000]()
{
print(" Timer Test2 5 sec ");
defer Test3();
defer Test1();
return 1;
}
main()
{
print("Start Timer Test2");
defer Test2();
}
https://tinypic.host/image/LzMcb
Now I really think that I'm using it wrong because not even the normal way doesn't work.
Code:
#include <a_samp>
main()
{
print(" Start Timer_Test2 5 sec");
SetTimer("Timer_Test2", 5000, false);
}
forward Timer_Test1();
forward Timer_Test2();
forward Timer_Test3();
public Timer_Test1()
{
print(" Why still working ? Why calling this timer 2x ?");
return 1;
}
public Timer_Test2()
{
print(" Timer Test2 5 sec ");
SetTimer("Timer_Test3", 6000, false);
SetTimer("Timer_Test1", 10000, false);
return 1;
}
public Timer_Test3()
{
print(" Timer Test3 6 sec ");
KillTimer(Timer_Test1());
return 1;
}
I found the right way.
Code:
#include <a_samp>
new test1;
new test2;
new test3;
main()
{
print(" Start Timer_Test2 5 sec");
test2 = SetTimer("Timer_Test2", 5000, false);
}
forward Timer_Test1();
forward Timer_Test2();
forward Timer_Test3();
public Timer_Test1()
{
print(" Why still working ? Why calling this timer 2x ?");
return 1;
}
public Timer_Test2()
{
print(" Timer Test2 5 sec ");
test3 = SetTimer("Timer_Test3", 6000, false);
test1 = SetTimer("Timer_Test1", 10000, false);
return 1;
}
public Timer_Test3()
{
print(" Timer Test3 6 sec ");
KillTimer(test1);
return 1;
}
Like I thought... I wasn't use it right ! Everything work just perfect !
This is how it works:
Code:
#include <a_samp>
#define YSI_NO_HEAP_MALLOC
#include <YSI_Coding\y_timers>
new Timer:test;
timer Test1[10000]()
{
print(" Why still working ? Why calling this timer 2x ?");
return 1;
}
timer Test3[2000]()
{
print(" Timer Test3 6 sec ");
stop Timer:test; // It seems that simply calls the function instantly and not stoping anything ... That's why calling the timer 2x
return 1;
}
timer Test2[5000]()
{
print(" Timer Test2 5 sec ");
defer Timer:Test3();
test = defer Timer:Test1();
return 1;
}
main()
{
print("Start Timer Test2 xx");
defer Timer:Test2();
}